1. Identify whether the integrand matches a standard derivative
Start from the integrand structure, not from a memorised list of tricks.
Identify whether the integrand already matches a standard antiderivative before searching for a technique.
JEE · Mathematics
Find indefinite integrals by recognising antiderivative structure and selecting substitution, integration by parts, partial fractions or trigonometric identities while preserving domains and the constant of integration.
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In short
An indefinite integral represents a family of antiderivatives. If F'(x)=f(x) on an interval, then ∫f(x)dx=F(x)+C.
Method selection matters: substitution requires a corresponding differential transformation, integration by parts reverses the product rule, and partial fractions requires a valid rational-function decomposition.
Official JEE syllabus documents define content scope. They do not publish chapter weightage, so none is asserted here.
Verified against the current JEE Main 2026 syllabus and JEE Advanced 2026 syllabus.
Where a Main-printed simple-integral family produces a closed form not shown on this page, that closed form requires Mathematics SME sign-off before publication.
This is a readiness check, not a weightage or scoring-priority list.
Start from the integrand structure, not from a memorised list of tricks.
Identify whether the integrand already matches a standard antiderivative before searching for a technique.
Choose an interval avoiding poles where required.
Check the integrand's real domain and choose a working interval that avoids poles or excluded points before integrating.
Substitution requires the differential, not just a change of symbol.
If u=g(x) and the integrand contains the corresponding g'(x)dx, transform the entire differential consistently, not merely relabel a variable.
For products, test parts only if the resulting integral is simpler.
For products of unlike functions, consider integration by parts, ∫u dv=uv-∫v du, only if it produces a simpler remaining integral.
Perform polynomial division on an improper rational function before partial fractions.
For rational functions, perform polynomial division if the integrand is improper, then factor the denominator and decompose into partial fractions.
Every indefinite integral answer ends with +C and a derivative check.
Add the constant of integration, then differentiate the final expression on the stated interval to confirm it reproduces the original integrand.
Match the integrand signal to the correct first method before integrating.
Known: the inner function x² has derivative 2x.
Method choice: substitution exactly matches the differential.
Let u=x², so du=2x dx. Then ∫2x cos(x²)dx = ∫cosu du = sinu + C. Back-substitute: sin(x²)+C.
Validity check: d/dx[sin(x²)+C] = cos(x²)·2x, which exactly reproduces the integrand.
The Main syllabus additionally prints families involving quadratic denominators, square-root quadratic forms and linear numerators over those forms; closed forms beyond this table require Mathematics SME sign-off before indexation.
Omitting +C on an indefinite integral.
Execution errorWhy it happens
An indefinite integral represents an entire family of antiderivatives, not a single function.
How it is corrected
Always append +C to a final indefinite-integral answer.
Calling a change of symbol 'substitution' without transforming the differential.
Decision / selection errorWhy it happens
Substitution requires the differential g'(x)dx to be present and transformed, not just a relabelled variable.
How it is corrected
Confirm du=g'(x)dx is genuinely present before calling the method substitution.
Using lnx instead of ln|x| for ∫dx/x on a general real interval.
Knowledge gapWhy it happens
lnx is undefined for x<0, but ln|x| is a valid antiderivative on both x>0 and x<0 branches.
How it is corrected
Write ln|x|+C and state the working interval when it excludes x=0.
Using partial fractions before polynomial division of an improper rational function.
Execution errorWhy it happens
Partial-fraction decomposition applies to a proper rational function; an improper one must be divided first.
How it is corrected
Check numerator versus denominator degree and divide first when the fraction is improper.
Using a formula across poles as though one antiderivative expression defines one connected interval.
Needs reviewWhy it happens
Antiderivative formulas are valid on a connected interval avoiding singularities; carrying one expression across a pole is invalid.
How it is corrected
State the interval explicitly and treat each side of a singularity separately.
Importing definite-integral properties onto an indefinite integral.
Knowledge gapWhy it happens
Properties such as limit reversal or interval addition apply to definite integrals with fixed limits, not to antiderivative families.
How it is corrected
Keep indefinite-integral reasoning separate from definite-integral property use.
FAQ
Straight answers about how Rank Sarthi fits into serious exam preparation.
Because differentiation removes constants, infinitely many antiderivatives differ only by a constant; +C represents that entire family.
When the integrand contains an inner function together with its derivative as a factor, matching the pattern g'(x)F(g(x)).
When the rational function is proper and its denominator factorises; an improper rational function must be divided first.
Because ln|x| is differentiable to 1/x on both x>0 and x<0, unlike lnx which is undefined for negative x.
Method classification for official Main-printed simple integral families is taught here; closed forms beyond the listed standard integrals require Mathematics SME sign-off before indexation. Use only verified official-paper provenance for worked examples. Do not publish counts or trends.
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