1. Fluid state
At rest, pressure at a point is isotropic and pressure changes with vertical depth.
At rest, pressure at a point is isotropic and pressure changes with vertical depth.
JEE · Physics
Choose the correct static-fluid or flow model and test every ideal-fluid or viscous-flow assumption before applying a formula.
Content status: draft. Verified academic content for this page has not been loaded yet, so the page is excluded from search indexing and the sitemap.
In short
Begin by deciding whether the fluid is at rest or moving. Static fluids are governed by pressure balance and buoyancy. Steady flow adds mass conservation through continuity. Bernoulli's equation adds mechanical-energy conservation under restrictive ideal-flow conditions. Viscous flow needs a resistance model such as Stokes' law when its conditions are satisfied.
Main names fluid-column pressure, Pascal's law, viscosity, Stokes' law, terminal velocity, flow regimes, critical velocity, and Bernoulli's principle. Advanced explicitly includes buoyancy and continuity, and explicitly excludes Poiseuille's equation from viscosity scope.
Surface energy, surface tension, contact angle, drops, bubbles, and capillarity are official topics but their focused production depth belongs to the dedicated Surface Tension route.
Prerequisite
Laws of Motion
Stabilise force balance before applying it to a fluid element or a submerged body.
Prerequisite
Work, Energy and Power
Review energy conservation before treating Bernoulli's equation as an energy statement.
Parent
JEE Physics
Subject hub for the Physics chapter set.
Parent
JEE syllabus
Exam-level official scope for every Physics, Chemistry and Mathematics unit.
This is a readiness check, not a weightage or scoring-priority list.
At rest, pressure at a point is isotropic and pressure changes with vertical depth.
At rest, pressure at a point is isotropic and pressure changes with vertical depth.
Pressure force acts normal to a surface. The net pressure force on a submerged body gives buoyancy.
Pressure force acts normal to a surface. The net pressure force on a submerged body gives buoyancy.
For steady incompressible flow in a tube, volume flow rate is constant across every cross-section.
Along a streamline in steady, incompressible, non-viscous flow, pressure, kinetic, and gravitational terms exchange while their sum stays constant.
Stokes' drag is a special low-speed result for a sphere, not a universal fluid-drag law.
Viscosity dissipates mechanical energy. Stokes' drag is a special low-speed result for a sphere, not a universal fluid-drag law.
Terminal velocity occurs when net force becomes zero, not when gravity disappears.
Terminal velocity occurs when net force becomes zero, not when gravity disappears.
Six decisions cover most Fluid Mechanics questions. Select the model before any algebra.
Pressure equals the perpendicular force divided by the area it acts over.
Normal force per unit area.
Use when — Finding average pressure for a uniform normal force.
Common trap — Using total force without isolating its normal component.
Pressure at depth equals surface pressure plus density times gravity times vertical depth.
Pressure at depth h below a free surface in a static fluid.
Use when — Static fluid with uniform density and constant g.
Common trap — Using the sloping path length instead of the vertical depth.
Buoyant force equals fluid density times displaced volume times gravity.
Buoyant force from the displaced fluid volume.
Use when — Hydrostatic fluid with effective uniform density.
Common trap — Using the whole object volume when the body is only partly submerged.
Flow rate equals area times speed, and area one times speed one equals area two times speed two.
Volume flow rate and incompressible continuity across a tube.
Use when — Steady one-dimensional average flow of an incompressible fluid.
Common trap — Conserving speed instead of conserving flow rate.
Pressure plus one half density times speed squared plus density times gravity times height stays constant along a streamline.
Bernoulli energy per unit volume along a streamline.
Use when — Steady, incompressible, non-viscous flow along a streamline, with no unaccounted pump or loss.
Common trap — Applying it across a viscous loss without correcting for it.
Stokes drag equals six pi times viscosity times radius times speed.
Stokes drag on a sphere of radius r.
Use when — Creeping flow around a sphere, unbounded-fluid approximation, low Reynolds-number regime.
Common trap — Using this for any shape or at a turbulent speed.
Terminal speed equals two times radius squared times the density difference times gravity, divided by nine times viscosity.
Terminal speed of a small sphere falling through a viscous fluid.
Use when — Stokes regime, isolated sphere, constant properties, steady terminal state.
Common trap — Ignoring buoyancy or container-wall effects.
Answer: v(t) = 2 r^2 (rho(s) minus rho(f)) g / (9 eta), valid only in the Stokes regime.
A sphere of density rho(s) and radius r falls through a fluid of density rho(f) and viscosity eta. At terminal speed the downward weight equals the upward buoyancy plus the Stokes drag.
Weight is (4/3) pi r^3 rho(s) g. Buoyancy is (4/3) pi r^3 rho(f) g. Stokes drag is 6 pi eta r v(t). Setting weight equal to buoyancy plus drag and solving for v(t) gives v(t) = 2 r^2 (rho(s) minus rho(f)) g divided by 9 eta.
The r squared dependence comes from a driving force proportional to volume, which scales as r cubed, opposed by Stokes drag which scales only as r. The ratio of the two leaves an r squared dependence in the terminal speed.
Treating pressure as a vector because pressure force has direction
Knowledge gapWhy it happens
Pressure itself is a scalar; only the force it produces on a chosen surface has a direction, normal to that surface.
How it is corrected
Compute pressure as a scalar, then apply it to a specific surface to get a directional force.
Comparing pressures using the length of an inclined liquid column instead of vertical height
Execution errorWhy it happens
Hydrostatic pressure depends only on vertical depth below the free surface, not on the path length through the fluid.
How it is corrected
Identify the vertical height between two points before applying the pressure-depth relation.
Applying Bernoulli between arbitrary points that are not connected by the modeled streamline
Decision / selection errorWhy it happens
Bernoulli's equation holds along a single streamline under steady, incompressible, non-viscous flow, not between any two arbitrary points in a fluid.
How it is corrected
Confirm both points lie on the same streamline and that the ideal-flow conditions hold before applying it.
Forgetting buoyancy in a terminal-speed force balance
Execution errorWhy it happens
Omitting buoyancy overstates the net driving force and gives an incorrect terminal speed.
How it is corrected
Write weight, buoyancy, and drag as three separate terms before balancing them.
Using Stokes' law at any speed or for any shape
Decision / selection errorWhy it happens
Stokes' law is a low Reynolds-number, creeping-flow result derived specifically for a sphere.
How it is corrected
Check the creeping-flow and spherical-particle conditions before applying Stokes' drag.
Reproducing surface-tension depth here instead of routing to its focused page
Needs reviewWhy it happens
Surface energy, surface tension, contact angle, drops, bubbles, and capillarity have their own dedicated production depth on a separate route.
How it is corrected
Route surface-tension questions to the Surface Tension chapter instead of expanding this page's scope.
Sources: JEE Advanced paper archive and NTA JEE Main question papers, linked in the sources section below.
FAQ
Straight answers about how Rank Sarthi fits into serious exam preparation.
Use its basic form for steady, incompressible, non-viscous flow along a streamline when no unaccounted machine work or loss occurs.
It is the constant speed reached when the net force on the moving body becomes zero.
The same steady volume flow rate must pass every cross-section, so a smaller area requires a larger average speed.
Evidence boundary: the syllabus mapping is tied to the official 2026 JEE Main and JEE Advanced documents, with Poiseuille's equation explicitly excluded from Advanced viscosity scope. No chapter weightage, question frequency, or forecast is asserted. Official papers are linked for evidence-safe practice, and any question classified by chapter requires human academic review first.
Contributor requirements for this page