JEE JEE Main and JEE Advanced · Mathematics

Probability

Construct a valid sample space, model events, select addition, multiplication, conditional, total-probability or Bayes reasoning correctly, and distinguish independence from mutual exclusivity.

Subject
Mathematics
Syllabus unit
Probability
  • Sample space and events precede any formula
  • Independence is not the same as mutual exclusivity
  • No invented weightage, question counts or trend percentages

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In short

Probability starts with a sample space and clearly defined events. Addition handles unions, multiplication handles intersections, conditional probability updates the sample space after information is known, and Bayes' theorem reverses a conditional direction through a partition.

Syllabus mapping

  • Unit
    Probability
    Topics
    Probability of an event, Addition and multiplication theorems of probability, Bayes' theorem, Probability distribution of a random variable, Conditional probability, independence and total probability (supporting reasoning)

What this chapter contains and why it matters

  • Question
    What is the chapter about?
    Direct answer
    Constructing sample spaces and events, then selecting addition, multiplication, conditional, total-probability or Bayes reasoning.
  • Question
    What is the central method choice?
    Direct answer
    Translate wording into set language, check mutual exclusivity vs independence, and validate denominators before conditioning.
  • Question
    Where do most mistakes begin?
    Direct answer
    Assuming outcomes are equally likely without justification, and treating mutually exclusive events as independent.
  • Question
    What should come before this chapter?
    Direct answer
    Permutations and Combinations for sample-space counting, and Sets and Relations for event modelling.
  • Question
    What comes after it?
    Direct answer
    Statistics extends random-variable mean and variance further.

The official JEE documents define content scope. They do not publish chapter weightage, so none is asserted here.

Official JEE syllabus mapping for Probability

Verified against the current JEE Main 2026 syllabus and JEE Advanced 2026 syllabus.

  • Concept group
    Explicit topic list
    JEE Main 2026
    Unit 13 explicitly includes probability of an event, addition and multiplication theorems of probability, Bayes' theorem and probability distribution of a random variable. Conditional probability, independence and total probability are not separately named in the Main wording.
    JEE Advanced 2026
    Explicitly includes random experiments, sample spaces, impossible/simple/compound events, addition and multiplication rules, conditional probability, independence, total probability, Bayes' theorem, and probability computation using permutations and combinations.

Sources: JEE Main 2026 syllabus and JEE Advanced 2026 syllabus, both linked in the sources section below.

Before this chapter

Concepts in this chapter

1. Define outcomes before counting them

A random experiment gives a sample space; events are subsets of it.

Define outcomes before counting them. Decide whether outcomes are equally likely before using favourable-over-total counting.

2. Translate the wording into set language

"Or" is union, "and" is intersection, "given" is conditioning.

Translate "or" to union, "and" to intersection and "given" to conditioning before selecting a formula.

3. Check mutual exclusivity vs independence

Check whether events are mutually exclusive or independent rather than assuming either.

If A and B are mutually exclusive and both have positive probability, then P(A∩B)=0 while P(A)P(B)>0, so they are not independent. This distinction must remain explicit.

4. Check denominators before conditioning

Conditional probability requires a positive denominator.

Check denominators before conditional probability, and for Bayes' theorem verify that the conditioning cases form an appropriate partition.

5. Validate the final probability bound

Every final probability must lie in [0,1].

Final probability must lie in [0,1]. A result outside this range signals a modelling or arithmetic error.

Method selector

  • Question signal
    "At least one"
    First model
    Complement is often efficient.
  • Question signal
    "A or B"
    First model
    Addition rule, with intersection check.
  • Question signal
    "A and B"
    First model
    Multiplication/conditional structure.
  • Question signal
    "Given B"
    First model
    Conditional probability, after P(B)>0.
  • Question signal
    Cause after observing an outcome
    First model
    Bayes, after partition validation.
  • Question signal
    Probability from arrangements/selections
    First model
    Build the P&C sample-space model first.
  • Question signal
    Random-variable table
    First model
    Validate probabilities before calculating mean or variance.

Formula sheet

  • P of A complement equals one minus P of A.

    Probability of the complement of A.

    Use when"Not A" questions.

    Common trapComplementing the wrong event.

  • P of A union B equals P of A plus P of B minus P of A intersection B.

    Probability of the union of two events.

    Use when"A or B" questions.

    Common trapAdding the intersection twice.

  • P of A union B equals P of A plus P of B, valid only when A intersection B is empty.

    Union probability for disjoint events.

    Use whenDisjoint events.

    Common trapUsing this for overlapping events.

  • P of A given B equals P of A intersection B divided by P of B, requiring P of B greater than zero.

    Probability of A given B has occurred.

    Use when"A given B" questions.

    Common trapZero denominator.

  • P of A intersection B equals P of B times P of A given B.

    Intersection probability via conditioning on B.

    Use whenSequential or intersection events, with P(B)>0.

    Common trapAssuming independence.

  • P of A intersection B equals P of A times P of B given A.

    Intersection probability via conditioning on A.

    Use whenSame as multiplication rule, conditioning on A, with P(A)>0.

    Common trapZero denominator in the conditional.

  • P of A intersection B equals P of A times P of B.

    Definition of independence for events A and B.

    Use whenTesting independence.

    Common trapConfusing independence with disjointness.

  • P of A equals the sum over i of P of A given B sub i times P of B sub i.

    Total probability via a partition of the sample space.

    Bᵢ
    pairwise disjoint, exhaustive partition with P(Bᵢ)>0

    Use whenCombining conditional routes.

    Common trapCases not exhaustive or overlapping.

  • P of B sub j given A equals P of A given B sub j times P of B sub j, divided by the sum over i of P of A given B sub i times P of B sub i.

    Reverses the conditioning direction through a partition.

    Bᵢ
    same partition conditions, plus P(A)>0

    Use whenReverse conditioning.

    Common trapMissing prior probabilities.

  • Each p sub i is nonnegative and the sum of all p sub i equals one.

    Validity condition for a discrete probability distribution.

    Use whenValidate a random-variable table.

    Common trapProbabilities not summing to 1.

  • E of X equals the sum of x sub i times p sub i.

    Expected value of a finite discrete random variable.

    Use whenAdvanced random-variable linkage.

    Common trapAveraging x-values without probabilities.

  • Variance of X equals the sum of x sub i minus mu, squared, times p sub i, which must be nonnegative.

    Variance of a finite discrete random variable.

    μ
    E[X]

    Use whenAdvanced random-variable linkage.

    Common trapNegative result from arithmetic error.

Worked examples

Two boxes are chosen with equal probability. Box A contains 2 red and 1 blue ball. Box B contains 1 red and 2 blue balls. One ball is drawn from the selected box and is red. Find the probability that Box A was selected.

Answer: 2/3

Known: P(A)=P(B)=1/2, P(R|A)=2/3, P(R|B)=1/3. A and B form a disjoint exhaustive partition of the box choice.

The question reverses the known conditional direction, so Bayes' theorem is appropriate.

P(A|R) = [(2/3)(1/2)] / [(2/3)(1/2)+(1/3)(1/2)] = (1/3)/(1/2) = 2/3.

Validity check: the answer lies in [0,1]. Observing red should favour Box A because Box A has the larger red proportion, so a posterior above 1/2 is directionally sensible.

Common mistakes and what they actually indicate

  • Assuming outcomes are equally likely without justification.

    Needs review

    Why it happens

    Favourable-over-total counting only applies when outcomes are actually equally likely.

    How it is corrected

    Justify the equally-likely assumption before using favourable-over-total counting.

  • Confusing union with intersection.

    Knowledge gap

    Why it happens

    "Or" and "and" translate to different set operations with different formulas.

    How it is corrected

    Translate the wording into union or intersection language before selecting a formula.

  • Treating mutually exclusive events as independent.

    Knowledge gap

    Why it happens

    If both events have positive probability, mutually exclusive events cannot be independent.

    How it is corrected

    Check both relationships separately rather than assuming one implies the other.

  • Cancelling conditional probabilities without a positive denominator.

    Execution error

    Why it happens

    Conditional probability is undefined when the conditioning event has probability zero.

    How it is corrected

    Check that the denominator is positive before using conditional probability.

  • Using Bayes without an exhaustive disjoint case structure.

    Decision / selection error

    Why it happens

    Bayes' theorem requires the conditioning cases to form a valid partition.

    How it is corrected

    Verify the partition is pairwise disjoint and exhaustive before applying Bayes' theorem.

  • Omitting prior probabilities.

    Recall gap

    Why it happens

    Bayes' theorem requires the prior probability of each partition case.

    How it is corrected

    List all prior probabilities before computing the Bayes numerator and denominator.

  • Computing a random-variable mean before validating the distribution.

    Decision / selection error

    Why it happens

    An invalid distribution makes any computed mean meaningless.

    How it is corrected

    Check pᵢ≥0 and Σpᵢ=1 before computing expectation or variance.

  • Producing a probability outside [0,1].

    Execution error

    Why it happens

    This signals a modelling or arithmetic error somewhere in the solution.

    How it is corrected

    Validate the final answer lies in [0,1] as a routine check.

Sources and provenance

Official syllabus scope verified against NTA JEE Main 2026 and JEE Advanced 2026 documents. No weightage, frequency or PYQ-count claim is made.

Contributor requirements for this page

  • Reviewer specialisation: probability, combinatorics and statistics.
  • Minimum: postgraduate Mathematics, Applied Mathematics, Statistics or equivalent.
  • Review scope: sample-space assumptions, all conditional denominators, independence criteria, total-probability partition conditions, Bayes denominator, random-variable distribution validity and worked example.