1. A source creates a field
A mass distribution creates a gravitational field around it.
A mass distribution creates a gravitational field around it. Every other mass placed in that field experiences a force.
JEE · Physics
Connect gravitational force, field, potential, energy, and orbital motion without mixing vector and scalar quantities.
Content status: draft. Verified academic content for this page has not been loaded yet, so the page is excluded from search indexing and the sitemap.
In short
Gravitation is an attractive inverse-square interaction. Gravitational field is force per unit test mass and points toward the source. Gravitational potential is potential energy per unit mass and is negative when zero is chosen at infinity.
Circular orbits result when gravity supplies centripetal acceleration; escape is an energy condition, not a powered climb at constant speed.
The official JEE documents define content scope. They do not publish chapter weightage, so none is asserted here.
Verified against the current JEE Main 2026 syllabus and JEE Advanced 2026 syllabus on 8 September 2026. This is a wording and scope mapping, not a claim about question difficulty or frequency.
Sources: JEE Main 2026 syllabus and JEE (Advanced) 2026 syllabus, both linked in the sources section below.
Prerequisite
Laws of Motion
Vectors, force balance, and Newton's laws underpin field and orbit reasoning.
Prerequisite
Work, Energy and Power
Work-energy reasoning is needed for potential, potential energy, and orbital energy.
Prerequisite
Kinematics
Circular-motion acceleration and graph reading support orbit and variation-of-g reasoning.
Parent
JEE Physics
Subject hub for the Physics chapter set.
Parent
JEE syllabus
Exam-level official scope for every Physics, Chemistry and Mathematics unit.
This is a readiness check, not a weightage or scoring-priority list.
A mass distribution creates a gravitational field around it.
A mass distribution creates a gravitational field around it. Every other mass placed in that field experiences a force.
The field g gives the acceleration of a test mass and points toward the source.
The field g gives the acceleration a test mass would experience at a point. It is a vector and points toward the source mass.
The scalar V makes energy changes easier: U equals m times V.
The scalar potential V makes energy changes easier to compute. Potential energy of a mass m in the field equals m times V.
For isolated masses, choosing V equal to zero at infinity makes bound-state potential and total energy negative.
For isolated masses, V equal to zero at infinity is the standard choice, so bound-state potential and total energy come out negative.
In a circular orbit, gravity changes the direction of velocity while speed remains constant. Gravity supplies exactly the centripetal force required.
Minimum escape speed makes the final total energy at infinity zero.
Minimum escape speed makes the final total energy at infinity zero, neglecting atmosphere and other bodies. Escape is not a constant force climbing at constant speed.
Six decisions cover most Gravitation questions. Select the model before any algebra.
Gravitational force equals G times the product of the two masses, divided by the square of the separation between their centres.
Mutual force magnitude between point masses.
Use when — Point masses, or spherically symmetric bodies evaluated outside their surface.
Common trap — Using altitude instead of centre-to-centre r.
Gravitational field equals minus G times M divided by r squared, directed toward the source along the radial unit vector.
Field of an isolated spherical mass M, at distance r, directed toward the mass.
Use when — Outside a spherically symmetric source.
Common trap — Dropping the inward direction and treating the field as a positive scalar.
Gravitational potential equals minus G M over r, and potential energy equals mass times potential.
Potential and potential energy with zero chosen at infinity.
Use when — Outside an isolated spherical source, with V equal to zero at infinity.
Common trap — Treating potential as a vector, or making it positive.
Orbital speed equals the square root of G M divided by r.
Circular-orbit speed.
Use when — Circular orbit of a satellite with negligible mass compared to a dominant central source.
Common trap — Using surface radius when the orbit altitude is nonzero.
Orbital period equals two pi times the square root of r cubed divided by G M.
Circular-orbit period.
Use when — Same conditions as the circular-orbit speed relation.
Common trap — Applying it directly to a noncircular trajectory.
Total orbital energy equals minus G M m divided by two r.
Total energy in a circular orbit.
Use when — Circular orbit, zero potential chosen at infinity.
Common trap — Confusing total energy with potential energy, which is minus G M m over r.
Escape speed equals the square root of two G M divided by r.
Minimum local escape speed.
Use when — No atmosphere, no propulsion after launch, other bodies neglected.
Common trap — Assuming the object reaches infinity with nonzero speed.
Gravity at height h equals surface gravity times the square of R over R plus h.
Variation of g above a spherical body at height h.
Use when — Outside a spherical Earth model.
Common trap — Using the small-height approximation g_0 times (1 minus 2h/R) when h is not small.
Gravity at depth d equals surface gravity times one minus d over R, for a uniform-density model.
Textbook depth result for g below the surface, at depth d.
Use when — Uniform-density spherical Earth model.
Common trap — Treating the linear result as an exact real-Earth law.
Answer: The least added energy is G M m divided by two r, and the speed changes from the orbital speed to the square root of two times the orbital speed.
Using altitude as r instead of adding the planetary radius
Execution errorWhy it happens
Force, field, and orbit formulas use the centre-to-centre distance, not height above the surface.
How it is corrected
Add the planetary radius to the altitude before substituting r.
Giving gravitational potential a vector direction
Knowledge gapWhy it happens
Potential is a scalar, energy per unit mass; only the field is a vector.
How it is corrected
Keep potential as a signed scalar and reserve direction for the field.
Forgetting that circular-orbit total energy is half the potential energy
Recall gapWhy it happens
Total energy in a circular orbit is minus G M m over two r, while potential energy is minus G M m over r.
How it is corrected
Derive total energy from kinetic plus potential energy rather than recalling it in isolation.
Using the uniform-density depth formula without naming its model
Needs reviewWhy it happens
The linear depth result assumes a uniform-density spherical Earth, which is not exact for the real Earth.
How it is corrected
State the uniform-density assumption whenever the depth formula is used.
Calling escape speed an acceleration or assuming a constant upward force is required
Knowledge gapWhy it happens
Escape speed is a velocity threshold set by energy conservation, not a description of a powered climb.
How it is corrected
Treat escape as reaching zero total energy at infinity, independent of the launch method.
Applying geostationary conditions to any orbit with a 24-hour period without checking plane and direction
Decision / selection errorWhy it happens
A geostationary orbit also requires the equatorial plane and a direction matching Earth's rotation.
How it is corrected
Check period, plane, and direction together before naming an orbit geostationary.
Official repositories: JEE Advanced paper archive and NTA JEE Main question papers.
FAQ
Straight answers about how Rank Sarthi fits into serious exam preparation.
With zero potential chosen at infinity, positive work is required to separate a bound mass to infinity, so its potential at a finite radius is negative.
Gravity provides the inward force required for the satellite's circular motion.
Its minimum magnitude at a point follows from energy conservation. A collision-free outward trajectory is also required by the physical setup.
Evidence boundary: the syllabus mapping is tied to the official 2026 JEE Main and JEE Advanced documents. No chapter weightage, question frequency, or forecast is asserted. Official papers are linked for evidence-safe practice, and any question classified by chapter, field, potential, g variation, circular orbit, Kepler relation, geostationary condition, or escape, requires human academic review first.
Contributor requirements for this page